Answer:
Both child tickets and senior tickets cost $14.
Step-by-step explanation:
Since the school that DeShawn goes to is selling tickets to the annual dance competition, and on the first day of ticket sales, the school sold 10 senior citizen tickets and 8 child tickets for a total of $ 252, while the school took in $ 280 on the second day by selling 10 senior citizen tickets and 10 child tickets, to determine what is the price of each of one senior citizen ticket and one child ticket, the following calculation must be performed:
10 senior tickets + 8 child tickets = 252
10 senior tickets + 10 child tickets = 280
280 - 252 = 2 child tickets
28 = 2 child tickets
28/2 = 1 child ticket
14 = 1 child ticket
14 x 10 = 140
(280 - 140) / 10 = senior tickets
140/10 = 14 = senior tickets
Therefore, both child tickets and senior tickets cost $14.
Answer:
x2 = -0.600000
x3 = -0.521600
Step-by-step explanation:
Given the formula;
xn+1 = (xn)³-5/10
x2 = (x1)³-5/10
Given x1 = -1
x2 = (-1)³-5/10
x2 = (-1-5)/10
x2 = -6/10
x2 = -0.600000
x3 = (x3)³-5/10
Given x3 = -0.6
x3 = (-0.6)³-5/10
x3 = (-0.216-5)/10
x3 = -5.216/10
x3 = -0.521600
3000 because the rate of change is from 27000 to 24000 so that's the rate of change but I have no idea what the percentage rate of change is omega lul
