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max2010maxim [7]

3 years ago

5

At a sale , dresses were sold for 35% of their original price. If the dresses originally cost 40$ each how much did a dress cost

on sale

1 answer:

Nimfa-mama [501]3 years ago

6 0

Answer:

$ 14

Step-by-step explanation:

$ 40 --- 100%

$ x --- 35%

x = 40*35/100 = 14

You might be interested in

You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly different from 0.36. With

Dafna11 [192]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.36 so then we need to conduct a two tailed test, the system of hypothesis are.:

Null hypothesis: $p=0.36$

Alternative hypothesis: $p \neq 0.36$

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.074)=0.0381$

Step-by-step explanation:

Data given and notation n

n represent the random sample taken

$\hat p$ estimated proportion of interest

$p_o=0.36$ is the value that we want to test

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.36 so then we need to conduct a two tailed test, the system of hypothesis are.:

Null hypothesis: $p=0.36$

Alternative hypothesis: $p \neq 0.36$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value .

Calculate the statistic

For this case the statistic is given:

$z = 2.074$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.074)=0.0381$

5 0

3 years ago

Can you help me with number 6? <br> Confused abit <br> Please

Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.

To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.

First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is

$\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}$

Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is

$\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}$

Third question:

To get exactly one six, it can either be the first, second or third roll.

In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.

In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus

$\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}$

And since there are three of these combinations, The answer is

$3\frac{5^2}{6^3}$

Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is

$1 - \frac{5^3}{6^3}$

4 0

3 years ago

Find the squares of (m-1)

Alchen [17]

Answer:

Solution

verified

Verified by Toppr

m

2

−3m−1=0

m

2

−3m=1 → (1)

Third term =(

2

1

coeeficientofm)

2

(

2

1

×(−3))

2

=(

2

−3

)

2

=

4

9

Adding

4

9

to both sides of equation (1), we get

m

2

−3m+

4

9

=1+

4

9

∴ m

2

−3m+

4

9

=

4

4+9

∴ (m−

2

3

)

2

=

4

13

Taking square roots on both sides

∴ m−

2

3

=±

2

13

∴ m=

2

3

+

2

13

or m=

2

3

−

2

13

m=

2

3+

13

,

2

3−

13

are the roots of the given quadratic equation.

8 0

2 years ago

Simplify (3x - 5) - (5x + 1).<br> 0-2x + 6<br> -2x - 6<br> 2x - 6<br> 2x + 6<br> fast please!

mamaluj [8]

-2x-6

EXPLANATION

(3x-5) = (-2x) - 6

3 0

3 years ago

If f(x) = 9x2 − x3, find f '(1) and use this value to find an equation of the tangent line to the curve y = 9x2 − x3 at the poin

yaroslaw [1]

Answer:

f(x)=9×2_x3=18 hope it help good luck

8 0

3 years ago