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Umnica [9.8K]
2 years ago
5

Solve for x A) 42 B) 40 C) 45 D) 38

Mathematics
1 answer:
alexgriva [62]2 years ago
3 0

Answer:

x = 40

Step-by-step explanation:

Using similarity theorem, we have the following:

\frac{24}{24 - 15} = \frac{x}{x - 25}

Solve for x

\frac{24}{9} = \frac{x}{x - 25}

Cross multiply

24(x - 25) = x(9)

24x - 600 = 9x

Subtract 24x from each side

- 600 = 9x - 24x

- 600 = -15x

Divide both sides by -15

40 = x

x = 40

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Help ASAP!! Geometry -
horrorfan [7]

Answer:

x = 9.27 cm

Volume = 289.2 cm³

Step-by-step explanation:

SA = Surface Area

SA = 229.2 cm²

P = Perimeter of Base

P = 3(6)

P = 18 cm

H = Height of Solid

H = x

A = Area of Base(Equilateral Triangle)

A = 6²√3 / 4

A = 36√3 / 4

A = 9√3

A = 9(1.732)

A = 31.176

A = 31.2 cm²

SA = Surface Area

SA = PH + 2A

229.2 = 18x + 2(31.2)

229.2 = 18x + 62.4

229.2 - 62.4 = 18x

166.8 = 18x

9.266 = x

9.27 = x

x = 9.27 cm

V = Volume

V = AH

V = 31.2(9.27)

V = 289.224

V = 289.2 cm³

8 0
2 years ago
The sum of 1/11 and 1/15 is closest to 0 1 or 2
vova2212 [387]
It is closer 1/11 is closer to 2 and 01 because it's smaller , 1/15 is also close but not as close
3 0
3 years ago
The cost of a movie ticket is increased by 15%. The old price was five dollars how much are they now?
Grace [21]

Answer:

5.75 is the answer.

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2 years ago
A red kangaroo can cover 40 feet in 1 jump.How Many feet can the red kangaroo cover in 12 jumps
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480 feet in 12 jumps
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4 0
3 years ago
Read 2 more answers
Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o
alekssr [168]
Draw a diagram to illustrate the problem as shown below.

The area of triangle acb is
A₁ = (1/2)*20*h = 10h

The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h

The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8

Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.

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3 years ago
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