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BigorU [14]
3 years ago
13

H(1) = -26 h(n) = h(n-1) x (-9) Find an explicit formula for h(n). h(n)= ___

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answer:

you do not have to state explicitly which limit law(s) you are using. 1 - 5n ... Q: 9) n(x) = 2x - 2 g(x)= x2 + 5 Find h(g(1) A) 5 B) 10 C) 21 D) 40.

Step-by-step explanation:

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Arrange the cards into three pairs of the same total.<br> -7,-5,-3,3,1,-1
ale4655 [162]

the answer is ( -7; 3) (-5; 1) ( -3;-1)

ok done. Thank to me :>

3 0
3 years ago
A cylinder has the diameter 4 and is 3 cm high what is the volume of the shape approximately​
Alex777 [14]

Step-by-step explanation:

diameter = 4cm

radius = 4/2 = 2cm

height = 3cm

volume of cylinder = πr²h

= 22/7 × 2 × 2 × 3

= 264/7cm³

= 37.714cm³

3 0
3 years ago
What is the sum of the angle measures in a dodecagon?<br><br> 1,440°<br> 2,160°<br> 1,800°<br> 150°
Vilka [71]
The sum of the angle measures in a dodecagon is 1,800 degrees

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7 0
3 years ago
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Halfway between 21,000 and 22,000 is?
Katena32 [7]
21,500 is the answer
4 0
3 years ago
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Pls help........
Zinaida [17]

Answer:

During the interval 0 < x < 2, height of the water balloon is increasing.

Step-by-step explanation:

Graph of the linear function represents the height f(x) of a balloon over the time 'x' seconds.

There are three intervals of the time in which height of the balloon has been given.

1). In the interval of 0 < x ≤ 2, height of the water balloon is increasing (Since slope of the line is positive or the line is slanting upwards).

2). In the interval 2 < x ≤ 3, height of the water balloon is constant (Since slope of the line is zero).

3). In the interval 3 < x ≤ 4, height of the water balloon is decreasing faster. (Since the given line is slanting downwards).

4). In the interval 4 < x < 6, height of the water balloon is decreasing (Since the given line in this interval is slanting downwards).

Therefore, during 0 < x < 2, height of the water balloon is increasing.

6 0
4 years ago
Read 2 more answers
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