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lana [24]
3 years ago
12

An ice cream store sells 2 ​drinks, in 4 ​sizes, and 6 flavors. In how many ways can a customer order a​ drink?

Mathematics
1 answer:
laiz [17]3 years ago
6 0
The answer is 48 different ways.
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. The AutoCorrect feature can automatically capitalize the first letter in the names of days.
Vinvika [58]
True. The AutoCorrect feature can automatically capitalize the first letter in the names of days.
4 0
3 years ago
Please help me with the simplifying
aliya0001 [1]

The key here is to not worry too much and just follow PEMDAS.

Here we have the expression (5\cdot 7)^2.  Following PEMDAS, we complete the expression inside the parentheses first, or 5\cdot 7 = 35. This gives us (35)^2 or just 35^2.

Hope this helps.

8 0
2 years ago
Benny is trying to learn how to ride a bike, but is terrified of falling. He did some research, and discovered that if he rides
Anestetic [448]

Answer:

a) 7.14% probability that Benny was learning to ride a bike using the training wheels

b) 28% probability that Benny was learning to ride a bike using the training wheels

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

Benny came home crying with a bruise on his knee, after falling. His mom is trying to guess how Benny was trying to learn to ride a bike.

a) Assuming that the probability that Benny was using each of these 3 methods is equal, what is the probability that Benny was learning to ride a bike using the training wheels?

So

Event A: Benny fell

Event B: Benny was using training wheels.

The probability that Benny was using each of these 3 methods is equal

This means that P(B) = \frac{1}{3}

He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;

This means that P(A|B) = 0.1

Probability of falling:

1/3 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.

1/3 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5

1/3 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then

P(A) = \frac{0.1 + 0.5 + 0.8}{3} = 0.4667

So

P(B|A) = \frac{\frac{1}{3}*0.1}{0.4667} = 0.0714

7.14% probability that Benny was learning to ride a bike using the training wheels

b) Since Benny's mom knows Benny so well, she knows that the probability that he was using training wheels is 0.7, regular bike is 0.2, and unicycle is 0.1. What is the probability now that Benny fell while using the training wheels?

Similar as above, just some probabilities change.

Event A: Benny fell

Event B: Benny was using training wheels.

The probability that he was using training wheels is 0.7

This means that P(B) = 0.7

He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;

This means that P(A|B) = 0.1

Probability of falling:

0.7 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.

0.2 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5

0.1 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then

P(A) = 0.7*0.1 + 0.2*0.5 + 0.1*0.8 = 0.25

So

P(B|A) = \frac{0.7*0.1}{0.25} = 0.28

28% probability that Benny was learning to ride a bike using the training wheels

7 0
4 years ago
What is the area of this rectangle
Setler [38]
A) 16 in2 :))))))))))))))))))))
3 0
3 years ago
If C(x) is the total cost incurred in producing x units of a certain commodity, then the average cost of producing x units of th
nataly862011 [7]

Answer:

x  =  2000 cameras

Step-by-step explanation:

C(x)     Total cost in producing  x units

C- = C(x) /x   Average cost of producing x units    x > 0

Cannon Precision Instrument

C (x)   Total monthly cost for producing x units of M1 cameras

is    C(x)  =  0.0025x²  + 80x  +  10000

Then average cost of producing x cameras M1 is

C-(x)  =  ( 0.0025x²  + 80x  +  10000)  /x

C-(x)  =   0.0025x  + 80  + 10000/x

Taking derivatives on both sides of the equation

C-´(x)   =  0.0025   -  10000/x²

Then

C-´(x)   = 0

( 0.0025x² - 10000 ) / x²   =  0

0.0025x² - 10000 =  0

x²  =  10000 /0.0025         x²  = 4000000

x  =  2000 cameras

8 0
3 years ago
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