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solniwko [45]
3 years ago
15

Could someone help me with a question?

Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0
Whats the question ill be happy to help
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On Friday 80% of the costumers who bought tickets at a movie theater also bought popcorn. There were 320 costumers who bought ti
Nimfa-mama [501]

Answer:

256

Step-by-step explanation:

I judt know I don't know hoet to explain sorry hope it helps

8 0
2 years ago
Read 2 more answers
Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.
Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{1599\text{ years}}

k=4.33\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 1000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=5.19g

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 10000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=0.105g

Thus, the amount after 10000 years will be, 0.105 grams.

4 0
3 years ago
Solve by completing the square<br>3x2 + x - 2 = 0​
DIA [1.3K]

Answer:

x = 2/3 or x = -1

Step-by-step explanation by completing the square:

Solve for x:

3 x^2 + x - 2 = 0

Divide both sides by 3:

x^2 + x/3 - 2/3 = 0

Add 2/3 to both sides:

x^2 + x/3 = 2/3

Add 1/36 to both sides:

x^2 + x/3 + 1/36 = 25/36

Write the left hand side as a square:

(x + 1/6)^2 = 25/36

Take the square root of both sides:

x + 1/6 = 5/6 or x + 1/6 = -5/6

Subtract 1/6 from both sides:

x = 2/3 or x + 1/6 = -5/6

Subtract 1/6 from both sides:

Answer:  x = 2/3 or x = -1

3 0
3 years ago
Please help me with math
dezoksy [38]

Answer:

Step-by-step explanation:

The answer is:

s= -1 and t = - 1

4 0
3 years ago
Which number line represtents the solution to |x+4|=2?​
vlada-n [284]

Answer:

Points -2 and -6 on the number line are the two solutions.

Step-by-step explanation:

Use the definition of absolute value as a starting point

|x|=x\,\,\mbox{for}\,\,x\geq 0\\|x|=-x\,\,\mbox{for}\,\,x

To solve the equation, you need to treat the two cases as above:

|x+4|=x+4=2\,\,\,\mbox{for}\,\,x+4\geq 0\implies x\geq -4\\x+4=2\implies x=-2

The solution x=-2 is consistent with the condition x>=-4, so it is the first and valid solution. Now the second case of the absolute value:

|x+4|=-(x+4)=2\,\,\,\mbox{for}\,\,x+4< 0\implies x

Again, the second solution -6 complies with the requirement that x<-4, so it is valid.

7 0
2 years ago
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