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puteri [66]
3 years ago
14

Find the solution to the equations. Will Mark Brainliest

Mathematics
2 answers:
vova2212 [387]3 years ago
7 0

Answer:

(- 1, 1 )

Step-by-step explanation:

Given the 2 equations

2x - y = - 3 → (1)

x + y = 0 → (2)

Adding the 2 equations term by term will eliminate the term in y, that is

3x = - 3 ( divide both sides by 3 )

x = - 1

Substitute x = - 1 into either of the 2 equations and solve for y

Substituting into (2)

- 1 + y = 0 ( add 1 to both sides )

y = 1

Solution is (- 1, 1 )

timofeeve [1]3 years ago
3 0

Answer:

(-1, 1)

Step-by-step explanation:

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F(x)=4x-1<br> G(x)=x+3<br> Find f(x)+g(x)
mr_godi [17]

Answer:

Answer is 5x+2

Step-by-step explanation:

Given \: f(x) = 4x - 1 \:  \: and \:  \\ g(x) = x + 3 \\ f(x) + g(x) = 4x -1    + x + 3 \\  = 5x + 2

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

8 0
3 years ago
Which is bigger 0.21, 21%
andrew11 [14]
21% is bigger than 0.21
5 0
3 years ago
Read 2 more answers
How do get 423 from the numbers 100, 50, 75, 3, 10 &amp; 7?
Rudik [331]
423 = 100 + 100 + 100 + 100 + 10 + 10 + 3

hope this helps


4 0
4 years ago
Read 2 more answers
A fruit stand has to decide what to charge for their produce. They need $10for 4 apples and 4 oranges. They also need $15 for 6
Nataly [62]

Answer:

Ok

Step-by-step explanation:

Ok

4 0
3 years ago
How many different integers between $100$ and $500$ are multiples of either $6,$ $8,$ or both?
nirvana33 [79]
We need to find the number of integers between 100 and 500 that can be divided by 6, 8, or both. Now, to do this, we must as to how many are divisible by 6 and how many are multiples of 8.

The closest number to 100 that is divisible by 6 is 102. 498 is the multiple of 6 closest to 500. To find the number of multiple of 6 from 102 to 498, we have

n = \frac{498-102}{6} + 1
n = 67

We can use the same approach, to find the number of integers that are divisible by 8 between 100 and 500. 

n = \frac{496-104}{8} + 1
n = 50

That means there are 67 integers that are divisible by 6 and 50 integers divisible by 8. Remember that 6 and 8 share a common multiple of 24. That means the numbers 24,  48, 72, 96, etc are included in both lists. As shown below, there are 16 numbers that are multiples of 24.

n = \frac{480-120}{24} + 1
n = 16

Since we counted them twice, we subtract the number of integers that are divisible by 24 and have a final total of 67 + 50 - 16 = 101. Hence there are 101 integers that are divisible by 6, 8, or both.

Answer: 101


8 0
3 years ago
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