Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere

The differential of V with respect to r is:

dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
Answer:
52
Step-by-step explanation:
55 - 3 = 52
give me brainiest wink wink
Answer:
12 cm
Step-by-step explanation:
The square of the length of the tangent segment is equal to the product of near and far distances to the circle from the point of intersection of the secant and tangent:
(8 cm)^2 = (4 cm)(4 cm +x)
16 cm = 4 cm +x . . . . . . divide by 4 cm
12 cm = x . . . . . . . . . . . . subtract 4 cm