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choli [55]
3 years ago
11

I need help PLEASE!!!

Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0

Answer:

1. ∠A and ∠B are right angles.                      Given

2. m∠A = m∠ B                                               All right angles are congruent.

3. ∠BEC≅ ∠AED                                              Vertical angles are congruent

4. ΔCBE ~ ΔDAE                                               AA

Step-by-step explanation:

A proof always begins with the givens.

1. ∠A and ∠B are right angles. -------------->Given

2. m∠A = m∠ B  are equal since----------->  All right angles are congruent.

3. ∠BEC≅ ∠AED  are also equal since---->Vertical angles are congruent

4. ΔCBE ~ ΔDAE since two angles are equal----------> AA

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Answer:  

Since, the coordinates of the given triangle are (0,0), (4,-4) and (-4,-2)

In the dilation by the scale factor k with centered at origin,

(x,y)\rightarrow (kx,ky)

Thus, If the dilation occurs by the scale factor of 2 with centered at origin,

New coordinates of the triangles are,

(0,0)\rightarrow (2\times 0, 2\times 0)

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3 years ago
Do inequalities have a range of solutions
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3 years ago
I need help solving this problem. Thanks
Kamila [148]

9514 1404 393

Answer:

  y = -4/7x +58/7

Step-by-step explanation:

The slope of the given line segment is ...

  m = (y2 -y1)/(x2 -x1)

  m = (17 -3)/(1 -(-7)) = 14/8 = 7/4

Then the slope of the perpendicular line is ...

  -1/m = -4/7 . . . . . slope of the perpendicular bisector.

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The midpoint of the given line segment is ...

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6 0
3 years ago
Aya = a1 + (n - 1)d
Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

Step-by-step explanation:

Given

  • a₁ = -33
  • d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

substituting a₁ = -33 and d = 4 in the nth term of the sequence

a_n=-33+\left(n-1\right)4

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a_n=4n-37

Thus, the nth term of the sequence is:

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now substituting n = 26 in the nth term to determine the 26th term of the sequence

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Therefore, the 26th term of an arithmetic sequence is:

a_{26}=67

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7 0
3 years ago
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