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posledela
3 years ago
11

Find the area of each figure. Round to the nearest hundredth where necessary. Only 1 and 5 please!

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0

Answer:

See below

Step-by-step explanation:

To begin, it is volume, not area

1. 8 x 12 x 17 = 1632 in ^3

5. 9 x 9 x 13.5 = 1093.5 in^3

If you want to find SURFACE AREA:

1. 2(8 x 12) + 2(8 x 17) + 2(17 x 12) = 872 in^2

5. 2(9 x 9) + 4(9 x 17) = 774 in^2

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sveticcg [70]
<span>We want to check how many intersections line A and B have, that is, we want to check how many common solutions do these equations have:
</span>
i) 2x + 2y = 8

ii) x + y = 4
<span>
use equation ii) to write y in terms of x as : y=4-x, 

substitute y =4-x in equation i):

</span>2x + 2y = 8
2x + 2(4-x) = 8
<span>2x+8-2x=8
8=8

this is always true, which means the equations have infinitely many common solutions.


Answer: </span><span>There are infinitely many solutions.</span><span>

</span>
4 0
3 years ago
Please help me with these. These are so hard.<br><br>​
LuckyWell [14K]

\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{a^6+b^6}\implies a^{2\cdot 3}+b^{2\cdot 3}\implies (a^2)^3+(b^2)^3 \\[2em] [a^2+b^2] [(a^2)^2-a^2b^2+(b^2)^2]\implies \boxed{(a^2+b^2)(a^4-a^2b^2+b^4)}

about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0
3 years ago
Vaughn is laying sod in his backyard. A diagram of his backyard is bel ow
Orlov [11]

Answer: A=944\ ft^2

Step-by-step explanation:

You need to use the following formula that is used to find the area of a trapezoid:

A=(\frac{M+m}{2})h

Where "M"and "m" are the bases of the trapezoid and "h" is the height of the trapezoid.

Based on the information given in the exercise, you can identify that:

M=c=36\ ft\\\\m=a=23\ ft\\\\h=b=32\ ft

Knowing these values, you can substitute them into the formula:

A=(\frac{36\ ft+23\ ft}{2})(32\ ft)

Finally, you must evaluate in order to find its area. This is:

A=(\frac{59\ ft}{2})(32\ ft)\\\\A=\frac{1888\ ft^2}{2}\\\\A=944\ ft^2

7 0
3 years ago
926 divided by 38 and remainder?​
docker41 [41]

Answer:

when 926 is divide by 38 it's remainder is 14.

6 0
3 years ago
Read 2 more answers
What the next pattern of A, C, E, G, I
algol13

Answer: A C E G I = 1 2 3 7 8

Step-by-step explanation: A C E G I K M O Q S U W Y AA AC AE AG AI AK AO AQ AU AW AY BA

5 0
2 years ago
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