Question

Which of the following statements have the same result? Explain each step in solving each one.

Answer 1

Answer:

Non of the above

I

$f(x) = 4x - 1 \\ f(1) = 4 - 1 \\ f(1) = 3$

II

$f(x) = 3x - \frac{1}{4} \\ {f}^{ - 1} (x) = \frac{1}{3x} + \frac{1}{12} \\ {f}^{ - 1} (2) = \frac{1}{6} + \frac{1}{12} \\ {f}^{ - 1} (2) = \frac{1}{4}$

III

$2y + 8 = 4y - 2 \\ - 2y = - 10 \\ y = 5$