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2 years ago

I need help with this

Mathematics

2 answers:

Harlamova29_29 [7]2 years ago

7 0

Answer:

50 degrees.

Step-by-step explanation:

The three angles make up a straight line angle which = 180 degrees, so:

C = 180 - 65 - 65

= 50 degrees.

Alekssandra [29.7K]2 years ago

6 0

Answer:

Step-by-step explanation:

So in forth-fifth grade you had to learn that a straight line is 180 degrees right? So the first thing that you do is you add 65+65 and then you get 130 degrees. But we're not done yet. Now we have to subtract 180 - 130 and you get 50 degrees. So the answer is 50 degrees.

Hope this helps! Please give Brainlist! Please!!

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Calaveras county in California imposes a 7.25% sales tax on goods purchased in that county. How much tax is imposed on a $56.96

MrRa [10]

The tax is 7.25% of $56.96.

7.25% of $56.96 =

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The answer rounds to $4.13

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2 years ago

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Oksana_A [137]

Answer:

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Step-by-step explanation:

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2 years ago

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Marysya12 [62]

Answer:

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3 years ago

Evaluate 2x + 1 when x = 7.

Tatiana [17]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

2. Use the following picture for this question:

Art [367]

Answer:

a. $24\sqrt{3}$ and 41.6

b. 52.1

Step-by-step explanation:

Considering the left side triangle the blue dotted side is the side "opposite" to the angle given and the side 24 is the side that is "adjacent" to the angle given. The trigonometric ratio tan relates opposite to adjacent. Also, let the blue dotted side be y.

<u>Note:</u> the exact value of tan 60 is $\sqrt{3}$

Thus, we can write $Tan(60)=\frac{y}{24}\\y=24*Tan(60)\\y=24*\sqrt{3} \\y=24\sqrt{3}$

Approximate value (rounded to nearest tenth): $24\sqrt{3} =41.6$

Considering the triangle to the right, the side "opposite" to the angle given (53 degrees) is 41.6 (just found in part (a)) and the side "hypotenuse" (side opposite to 90 degree angle) is x. The trigonometric ratio sine relates opposite and hypotenuse.

Thus we can write and solve:

$Sin(53)=\frac{41.6}{x}\\x=\frac{41.6}{Sin(53)}=52.1$

4 0

3 years ago