1st problem:
Use the Pythagorean theorem:
a^2+b^2=c^2
49+361=c^2
c^2=410
c=20.24
The answer is 20m
2nd problem:
First calculate the height using the Pythagorean theorem:
a^2+b^2=c^2
20^2+b^2=625 (i got 20 {radius} by half-ing the base edge length)
400+b^2=625
b^2=225
b=15
Next, solve for the volume:
V=a^2*h/3
V=40^2*15/3
V=1600*5
V=8000
The answer is the second choice or B.
Answer:
3rd group of possible answers is the correct set
Step-by-step explanation:
Each of the three points in the 3rd line of possible answers is a solution of the given equation, as can be verified by substitution:
If x = -2, y = -8(-2) = +16
If x = 3, y = -8(3) = -24
If x = -4, y = -8(-4) = +32
Uh it can really be anything. You should try and be more specific: see if you did the whole problem.
Answer:
5
Step-by-step explanation:
For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.
Also, two physically quantities can only be added or subtracted only when their dimension are same.
here all option are dimensionally correct except the 5th option where
dimension of t= [T] whereas dimension of a/v is 
= T^{-1}
since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.
