Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
<span>The next letter is 'n'. The pattern misses a letter after a pair of letters, for example: 'a' and 'b' are a letter pair, then 'c' is skipped, then the letter pair 'd' and 'e' comes next. For every other letter pair, the order is reversed so they are not in alphabetical order. The next letter pair is 'm' and 'n', and because the pair 'j' and 'k' is in alphabetical order, this pair must be reversed. Therefore, the next letter is 'n'.</span>
If this is in value, you would have $5,060. If you mean bills it would be 560.
The Sample space for three cards is
There are two cards red(R) and black(B) and a six-sided die.
The event is one card is picked randomly and then rolls the die.
So, the Sample space is as follows.
<h3>Find Sample space if there are three cards.</h3>
Consider there were three cards red(R), black(B) and green(G) a six-sided die.
The event is one card is picked randomly and then rolls the die.
So, the sample space will be as follows,
.
Learn more about sample space here :-
brainly.com/question/24273864
#SPJ1
Answer: 42 in all, 14 of each.
Step-by-step explanation
The color with the least amount of balloons is orange with 14. this means to have an equal amount of balloons for each color, you would need 14 of each color.
