Coach Stevens needs to purchase sprinklers to water the baseball field. The standard distance between bases is 90 feet and the i
nfield is a perfect square.
Coach Stevens found one sprinkler that sprays a maximum distance of 50 feet.
If Coach Stevens placed the sprinkler on the pitcher's mound, would the water spray so that the entire infield was watered? Justify your response.
Coach Stevens found one sprinkler that sprays a maximum distance of 50 feet.
If Coach Stevens placed the sprinkler on the pitcher's mound, would the water spray so that the entire infield was watered? Justify your response.
1 answer:
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Answer:
Width = 11 yards
Length = 17 yards
Step-by-step explanation:
First of all, the length of the rectangle is 6 yards longer than the width, this means, length = width + 6 yards. This dimensions can be represented on figure 1, where <em>w</em> is width, and <em>l</em>, for length.
We know the area of a rectangle is A = width x length
For our case 187 = w . (w + 6)
Using the Distributive Property for the multiplication we obtain
Using the quadratic formula where a = 1, b = 6, c = - 187 and replacing into the formula, we will have:
We have two options:
Or
But a distance (width) can not be negative so, this answer for w must be discarded.
The answer must be width = 11 yards.
To find the length
