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3 years ago

Determine the area of the BLUE triangle.

Mathematics

1 answer:

Cloud [144]3 years ago

3 0

The answer should be 147.

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15 times the square of a nonzero number is equal to 20 times the number

melisa1 [442]

Answer:

Let the number be x

The expression above is written as

15x² = 20x

Divide both sides by x

We get

15x²/x = 20x/x

15x = 20

Divide both sides by 15

x = 20/15

x = 4/3

Hope this helps

4 0

3 years ago

Find the missing side lengths. Leave your answers as radicals in simplest form. *

lora16 [44]

That's the isosceles right triangle, one of the two cliche triangles students are expected to learn. The sides of the 45°/45°/90° triangle are in the ratio 1:1:√2.

So v= 3√2 (the two legs are equal) and hypotenuse u = √2 × v = 6.

Answer: C

8 0

3 years ago

Is my answer correct? If its not, would you mine telling me what is correct?

Luden [163]

Answer:

Sorry but you have the y and x mixed up

Step-by-step explanation:

You have them mixed up

6 0

3 years ago

Read 2 more answers

All of the following are equivalent except _____.

Y_Kistochka [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

Given: circle k(O), mAM=125°, mEF=31°, m∠MAF=75° Find: m∠AME

myrzilka [38]

Answer:

The measure of angle A.M.E is $58\°$

Step-by-step explanation:

step 1

Find the measure of arc M.E

we know that

The inscribed angle is half that of the arc it comprises.

$m$

we have

$m$

$arc\ E.F=31\°$

substitute the values

$75\°=\frac{1}{2}(arc\ M.E+31\°)$

$150\°=(arc\ M.E+31\°)$

$arc\ M.E=150\°-31\°=119\°$

step 2

Find the measure of arc A.F

we know that

$arc\ M.E+arc\ E.F+arc\ A.F+arc\ A.M=360\°$ -----> by complete circle

substitute the values

$119\°+31\°+arc\ A.F+125\°=360\°$

$119\°+31\°+arc\ A.F+125\°=360\°-275\°=85\°$

step 3

Find the measure of angle A.M.E

we know that

The inscribed angle is half that of the arc it comprises.

$m$

substitute the values

$m$

5 0

4 years ago