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2 answers:
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Answer:
{5π/6, 11π/6}
Step-by-step explanation:
Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.
The solution to this equation is ...
cot(θ) = -√3
so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.
Answer:
The bottom cutoff heights to be eligible for this experiment is 66.1 inches.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Mean of 69.0 inches and a standard deviation of 2.8 inches.
This means that
What is the bottom cutoff heights to be eligible for this experiment?
The bottom 15% are excluded, so the bottom cutoff is the 15th percentile, which is X when Z has a pvalue of 0.15. So X when Z = -1.037.
The bottom cutoff heights to be eligible for this experiment is 66.1 inches.