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3 years ago

Determine whether each expression is equivalent to x3−25x. Select Yes or No for each expression.

Mathematics

1 answer:

dem82 [27]3 years ago

5 0

Answer:

I’m so sure, but I’ll try.

1. Yes

2. No

3. No

4. Yes

5. No

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All sides of quadrilateral ABCD are tangent to circle P.

VARVARA [1.3K]

Answer:

44.4 units

Step-by-step explanation:

Recall: 2 tangents drawn from an external point from a circle are congruent

Perimeter of the quadrilateral = AB + BC + CD + AD

AB = 3.1 + 8 = 11.1

BC = 3.1 + 8 = 11.1

CD = 11.1 (given)

AD = 8 + 3.1 = 11.1

Perimeter = 11.1 + 11.1 + 11.1 + 11.1

= 44.4 units

6 0

3 years ago

When does an electrically charged object attract another object?

pickupchik [31]

Answer:

Two objects that have excess opposite charges, one positively charged and the other negatively charged, attract each other when relatively near.

6 0

2 years ago

Given a pair parallel lines cut by a transversal same interior angles are supplementary?

makkiz [27]

If 2 parallel lines are cut by a transversal, then the alternate exterior angles are congruent. If 2 parallel lines are cut by a transversal, then the same side interior angles are supplementary. A line that intersects 2 coplanar lines at 2 different points.

6 0

3 years ago

Luke and Matthew ran a lemonade stand on Saturday they agree that Matthew would get 60% of the profit because the lemonade stand

cupoosta [38]

0.6 times 25 = 15

Matthew gets $15

Luke gets $10

Hope this Helps!

8 0

3 years ago

svetlana [45]

Answer:

$\large \boxed{\sf \text{The rate of the boat is } 53 \ km/h \text{, the rate of the current is }8\ km/h \ \ }$

Step-by-step explanation:

Hello, let's note v the rate of the boat and r the rate of the current. We can write the following

$\dfrac{135}{v-r}=3=\dfrac{183}{v+r}$

It means that

$135(v+r)=183(v-r)\\\\135 v + 135r=183v-183r\\\\\text{ *** We regroup the terms in v on the right and the ones in r to the left***}\\\\(135+183)r=(183-135)v\\\\318r=48v\\\\\text{ *** We divide by 48 both sides ***}\\\\\boxed{v = \dfrac{318}{48} \cdot r= \dfrac{159}{24} \cdot r}$

But we can as well use the second equation:

$3(v+r)=183\\\\v+r=\dfrac{183}{3}=61\\\\\dfrac{159}{24}r+r=61\\\\\dfrac{159+24}{24}r=61\\\\\boxed{r = \dfrac{61*24}{183}=8}$

and then

$\boxed{v=\dfrac{159*8}{24}=53}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago