All sides of quadrilateral ABCD are tangent to circle P.
1 answer:
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<u>Answer:</u>
<u>Step-by-step explanation:</u>
------------(1) (given)
-------------(2) (given)
so,
f(x) = h(g(x)) (given)
= -----(from (1) and (2))
⇒-----(taking g(x) = k)
⇒ is the function.
Answer:
Step-by-step explanation:
sin²β + sin²β×tan²β = tan²β
sin²β( 1 + tan²β ) = tan²β
~~~~~~~~~~~~~~~~
<u><em>sin²β + cos²β = 1 </em></u>
<u><em /></u> +
=
⇒ tan²β + 1 = sec²β ⇔ 1 + tan²β = sec²β
~~~~~~~~~~~~~~
1 + tan²β =
L.H. = sin²β ( ) = tan²β
R.H. = tan²β