We have 5% and 6.5% acetic acid solutions and we need 200 ml of 6% acetic acid.
Set up two equations:
f means 5% and s means 6.5%
A) f + s = 200
B) .05f + .065s = (.06 * 200)
Multiplying equation A by -.05
A) -.05f -.05s = -10
B) .05f + .065s = 12 then adding both equations:
.015s = 2
<span>
<span>
<span>
we need 133.33</span> ml of 6.5% acetic acid and
66.67 ml of 5% acetic acid solution.
</span> </span>
Source:
http://www.1728.org/mixture.htm
36 is the answer yes yes yes
yes because she would only use 96 gallons of gas and still have 4 gallons left.
Answer:
n=150
Step-by-step explanation:
(-17+n/5)-13=0
-17= -17/1 = -17(5)/5
-17(5)+n/5 = n-85/5
(n-85)/5-13=0
13=13/1 =13(5)/5
(n-85)-(13(5))/5 =n-150/5
(n-150)/5=0
n-150=0
n=150
7ئنرص9رفچن9خبپ چکصر3ஸூஸ்ரீமத9uned20ijwndccb8uo0ecd
