7/12-9/8(2x-1)-5/6(3x+2)=0
(7*2-9(2x-1)*3-5(3x+2)*4)/24=0
(14-9(2x-1)*3-5(3x+2)*4)/24=0
(14-27(2x-1)-20(3x+2)/24=0
(14-54x+27-60x-40)/24=0
(14+(-54x-60x)+27-40)/24=0
(14-114x+27-40)/24
(-144x+1)/24=0
-114x+1=0
-114x=-1
x=1/144
The distribution shaped for which the mean and median must be about the same will be:
D. Symmetric
E. uniform
<h3>How to illustrate the information?</h3>
In a symmetric distribution, the median is equal to the mean. The bell-shaped distribution is same as the standard normal distribution.
In a right-skewed distribution, the median is much less than the mean and a bimodal distribution is one with two modes.
Therefore, the correct options are D and E.
Learn more about mean on:
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Answer:
she got back 63 times
Step-by-step explanation:
Here, we want to know the number of times she is at bat
from the question, we are made to know that she strikes out twice after 9 times
So striking out 14 times, the number of times she has got back will be ;
14/2 * 9 = 63 times
This is a fairly tedious problem. The only way to solve that I see is to simply list out all the possible cases and go through each one by one. You'll use the triangle inequality theorem to see if the triangles can be formed. The theorem says that a+b > c must be true for all sets of pairs. In other words, take any two sides and add them up. The sum must be greater than the third side.
Going through all the combos possible (that I could find), this is what I got
Blue9,Green7,Orange4
Blue9,Green7,Purple12
Blue9,Green7,Red3
Blue9,Green7,Yellow5
Blue9,Orange4,Purple12
Blue9,Purple12,Yellow5
Green7,Orange4,Yellow5
Green7,Red3,Yellow5
Orange4,Red3,Yellow5
In all, I count 9 cases. So the answer to problem 1 is 9.
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For problem 2, the best way may be to pick two segments at a time instead of one. However, I have a feeling that will take just as long as the first method. I haven't tried it out. Even though going through the rods one at a time takes a while, it's probably the best option so you don't overlook any cases.
Answer:
1. AT = 9.43
2. TH = 9.43
3. MA = 7.81
4. MH = 7.81
Step-by-step explanation:
1. Determination of the length of AT.
Length of 1st leg = 8
Length of 2nd leg = 5
length of AT =.?
Using pythagoras theory, we can obtain the length of AT as illustrated below:
AT² = 8² + 5²
AT² = 64 + 25
AT² = 89
Take the square root of both side
AT = √89
AT = 9.43
2. Determination of the length of TH.
From the diagram given in the question above, we can see that length TH and length AT are the same i.e
TH = AT
AT = 9.43
Therefore,
TH = 9.43
3. Determination of the length of MA.
Length of 1st leg = 6
Length of 2nd leg = 5
Length of MA =?
Using pythagoras theory, we can obtain the length of MA as illustrated below:
MA² = 6² + 5²
MA² = 36 + 25
MA² = 61
Take the square root of both side
MA = √61
MA = 7.81
4. Determination of the length of MH.
From the diagram given in the question above, we can see that length MH and length MA are the same i.e
MH = MA
MA = 7.81
Therefore,
MH = 7.81
