Answer:
3.33 and 1/3
Step-by-step explanation:
"Dense" here means that there are infinite irrational numbers between two rational numbers. Also, there are infinite rational numbers between two rational numbers. That's the meaning of dense. Actually, that can be apply to all real numbers, there always is gonna be a number between other two.
But, to demonstrate that irrationals are dense, we have to based on an interval with rational limits, because the theorem about dense sets is about rationals, and the dense irrational set is a deduction from it. That's why the best option is 2, because that's an interval with rational limits.
The possible solution is 12 cats and 4 dogs in Sarah's store.
Let x represent the number of cats and y represent the number of dogs.
Since Sarah's Pet Store never has more than a combined total of 16 cats and dogs. Hence:
Also, She also never has more than 9 cats. Therefore:
The solution to the inequality is graphed. From the graph, the possible solution is 12 cats and 4 dogs
Find out more on inequalities at: brainly.com/question/24372553
Answer:
i think this is what your looking for
Step-by-step explanation:
the relationship is that they always go up by 40
An outside angle is equal to the sum of the two opposite inside angles.
The two opposite inside angles from X are 63 and 46.
X = 63 + 46 = 109 degrees.
1.
The first transformation, the translation 4 units down, can be described with the following symbols:
(x, y) → (x, y-4).
as the points are shifted 4 units vertically, down. Thus the x-coordinates of the points do not change.
A'(1, 1) → A"(1, 1-4)=A"(1, -3).
B'(2, 3) → B"(2, 3-4)=B"(2, -1).
C'(5, 0) → C"(5, 0-4)=C"(5, -4).
2.
The second transformation can be described with:
(x, y) → (x, -y).
as a reflection with respect to the x-axis maps:
for example, (5, -7) to (5, 7), or (-3, -4) to (-3, 4)
thus, under this transformation A", B", C" are mapped to A', B' and C' as follows:
A"(1, -3)→A'(1, -(-3))=A'(1, 3)
B"(2, -1)→B'(2, -(-1))=B'(2, 1)
C"(5, -4)→C'(5, -(-4))=C'(5, 4)
Answer:
A'(1, 3), B'(2, 1), C'(5, 4)
