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andrew-mc [135]
3 years ago
9

Find the midpoint of the segment with the following endpoints. (6, 4) and (9, 1)​

Mathematics
1 answer:
joja [24]3 years ago
3 0

Answer:

(\frac{15}{2},\frac{5}{2})

Hope this helps!

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Suppose the expected returns on equity of two firms, Macrosoft and Microsoft, that operate in the same business are 10.50% and 1
Komok [63]

Answer:

The return on assets in this business for Macrosoft is

ROA = 10.50%

Step-by-step explanation:

Return on Equity:

ROE represents how much a firm is generating profits by using the shareholder's money.

ROE is calculated as

$ {ROE = \frac{Annual \:\: net\: \: income}{Average \:\: shareholder's \:\: equity} $​  ​

Return on Assets:

ROA represents how much a firm is generating profits for every dollar of its assets.

ROA is calculated as

$ {ROA = \frac{Annual \:\: net\: \: income}{Total \:\: assests} $​  ​ ​

What is the return on assets in this business if Macrosoft has no debt?

Debt plays an important role in the calculations of return on assets.

We know that

Assets = Liabilities + Equity

Since the Macrosoft has no debt, its return on assets will be same as return on equity.

Assets = Equity

ROA = ROE

ROA = 10.50%

5 0
3 years ago
PLEASE I REALLY NEED HELP PLEASE!!!!!!
DochEvi [55]

I think that can help for now

7 0
3 years ago
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
3 years ago
Maryanne sells cruise vacations.
grandymaker [24]

Answer:

fcriohewdsajiodsx

Step-by-step explanation:

oing this for something! tewsting

4 0
3 years ago
Read 2 more answers
What is 25 1/2 divided by 6 1/4
Kisachek [45]
4.08, or 4 2/25 :) hope this helps
6 0
4 years ago
Read 2 more answers
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