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RUDIKE [14]
3 years ago
6

Please help!!! Explain and correct the error in this calculation.

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

for more math help use the app called connects

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If on the other hand a > 0, then the parabola would open upward.

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3 years ago
PLEASE HELP ASAP!!!!
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It is easy! I got you! So if Gavin earned $25 more then Seiji and the total of money they got over the summer is $425, all you have to do is subtract, so 425- 25= 400. Seiji earned s and Gavin earned g.

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maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

A = \frac{\theta}{360} * \pi r^2 --- sector area

L = \frac{\theta}{360} * 2\pi r ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

A = \frac{\theta}{360} * \pi r^2

So, we have:

A = \frac{160}{360} * \frac{22}{7} * 5^2

Evaluate

A = 34.92

The arc length is:

L = \frac{\theta}{360} * 2\pi r

So, we have:

L = \frac{160}{360} * 2 * \frac{22}{7} * 5

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

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8 0
2 years ago
A 31-in. television has a 31 in. diagonal and a 18 in. width. what is the height of the 31-in. television?
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<span>By the Pythagorean theorem:

</span>height = \sqrt{31^2-18^2}= \sqrt{961-324}= \sqrt{637}\approx25.24 \ in<span>


</span>
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A construction company is analyzing which of its older projects need renovation. Building B was built two years before building
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Step-by-step explanation:

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