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Sonja [21]
3 years ago
9

What is the approximate surface area of a cylinder that's base has a radius of 2, and it's lateral rectangle has a length of 6.2

8, and a width of 4?
Mathematics
1 answer:
Kisachek [45]3 years ago
7 0

Answer:

Surface area of cylinder = 50.26 unit² (Approx.)

Step-by-step explanation:

Given:

Radius of base r = 2 units

Width of lateral rectangle = 4 units

Length of lateral rectangle = 6.28 units

Find:

Surface area of cylinder

Computation:

Surface area of cylinder = 2[Area of base] + Area of lateral rectangle

Surface area of cylinder = 2[πr²] + [l][b]

Surface area of cylinder = 2[(22/7)(2)²] + [6.28][4]

Surface area of cylinder = 2[(22/7)(4)] + 25.12

Surface area of cylinder = 25.14 + 25.12

Surface area of cylinder = 50.26

Surface area of cylinder = 50.26 unit² (Approx.)

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