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BARSIC [14]
3 years ago
15

So, she was making $9/hr, then she's da bomb so she got a raise of 150%.

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0
The amount of money Maria now makes per hour = $22.5
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The temperature of a city changed -24 degrees Celsius over a 6 week period. Write an expression the show the average change in t
Ne4ueva [31]

Answer:

The expression is (-24) / 6 = -4degrees which means that in each week the average change in temperature was -4 degrees Celsius.

Step-by-step explanation:

Change in a quantities can as well be interpreted as rate of change which is used in many everyday problems, such as weather forecast, traveling , in science and so on.When we are talking about rate of change it's is usually in ratio such as Miles per hour or feet per second can be used in calculation involving rates of speed. It is how one quality is changing with respect to time , for instance, rate equals distance divided by time: r = d/t.

In finance rate of change is also applicable we can have Unit price which is a particular rate that compares a price to some unit of measure. Example is $64 per dozen.

Therefore, Given from the question,

The temperature of a city changed -24 degrees Celsius ,

Time =6 weeks period.

Then change is r = d/t.

= (-24) / 6

Change = (-24) / 6 = -4 degrees

This means that each week the average change in temperature was -4 degrees Celsius.

3 0
4 years ago
Consider the initial value problem y′+2y=4t,y(0)=8.
Xelga [282]

Answer:

Please read the complete procedure below:

Step-by-step explanation:

You have the following initial value problem:

y'+2y=4t\\\\y(0)=8

a) The algebraic equation obtain by using the Laplace transform is:

L[y']+2L[y]=4L[t]\\\\L[y']=sY(s)-y(0)\ \ \ \ (1)\\\\L[t]=\frac{1}{s^2}\ \ \ \ \ (2)\\\\

next, you replace (1) and (2):

sY(s)-y(0)+2Y(s)=\frac{4}{s^2}\\\\sY(s)+2Y(s)-8=\frac{4}{s^2}  (this is the algebraic equation)

b)

sY(s)+2Y(s)-8=\frac{4}{s^2}\\\\Y(s)[s+2]=\frac{4}{s^2}+8\\\\Y(s)=\frac{4+8s^2}{s^2(s+2)} (this is the solution for Y(s))

c)

y(t)=L^{-1}Y(s)=L^{-1}[\frac{4}{s^2(s+2)}+\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+L^{-1}[\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}

To find the inverse Laplace transform of the first term you use partial fractions:

\frac{4}{s^2(s+2)}=\frac{-s+2}{s^2}+\frac{1}{s+2}\\\\=(\frac{-1}{s}+\frac{2}{s^2})+\frac{1}{s+2}

Thus, you have:

y(t)=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}\\\\y(t)=L^{-1}[\frac{-1}{s}+\frac{2}{s^2}]+L^{-1}[\frac{1}{s+2}]+8e^{-2t}\\\\y(t)=-1+2t+e^{-2t}+8e^{-2t}=-1+2t+9e^{-2t}  

(this is the solution to the differential equation)

5 0
3 years ago
Simplify.<br><br> 1/4y+1 1/2+2−1 3/4y−12
valina [46]

Answer:

2y+9 1/2

Step-by-step explanation:

the answer is 2y+9 1/2 because 1/4y+1 3/4y=2y and 1 1/2+2+ (-12) (12 is negative because its minus 12)=9 1/2 so the answer is 2y+9 1/2

4 0
3 years ago
How do you simplify slope?
mojhsa [17]

Answer:

Sometimes this fraction can be further simplified by dividing the numerator and the denominator by their greatest common factor. ... Divide the numerator by this number. If the result is zero, the simplified slope of the line is also zero.

Step-by-step explanation:

3 0
3 years ago
How do I solve!!!!!!!!!! plsss
Solnce55 [7]
I think it might be -3
5 0
3 years ago
Read 2 more answers
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