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zaharov [31]
3 years ago
15

I need help with this question and no links or I will report you

Mathematics
1 answer:
dem82 [27]3 years ago
4 0
A: 0.748≈0.75(.88x.85)
B.1.63 (.88x1.85)
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lilavasa [31]

Answer:

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Step-by-step explanation:

\because \:  \sin(90 \degree -  \theta) =  \cos \theta \\ \therefore \:  \sin(90 \degree - 5 \theta) =  \cos 5\theta....(1) \\  \\ \sin(90 \degree - 5 \theta) = \cos(180 \degree -  \theta)...(2) \\ from \: (1) \: and \: (2) \\ \cos 5\theta = \cos(180 \degree -  \theta) \\ 5 \theta = 180 \degree -  \theta \\  5 \theta  + \theta= 180 \degree  \\ 6\theta= 180 \degree  \\  \theta =  \frac{180 \degree}{6}  \\  \\  \huge \red{ \boxed{\theta = 30 \degree}}

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3 years ago
Which is the polynomial function of lowest degree with rational real coefficients, a leading coefficient of 3 and roots StartRoo
anastassius [24]

Answer:

a) f(x)=3x^{3}-6x^{2}-15x+30

Step-by-step explanation:

1) In this question we've been given "a", the leading coefficient. and two roots:

x_{1}=\sqrt{5}\:x_{2}=2

2) There's a theorem, called the Irrational Theorem Root that states:

If one root is in this form x'=\sqrt{a}+b  then its conjugate x''=\sqrt{a}-b. is also a root of this polynomial.

Therefore

x_3=-\sqrt{5}

3) So, applying this Theorem we can rewrite the equation, by factoring. Remembering that x is the root. Since the question wants it in this expanded form then:

f(x)=3(x-\sqrt{5})(x+\sqrt{5})(x-2)\Rightarrow 3x^{3}-6x^{2}-15x+30

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tens ones      decimal point      tenths  hundredths  thousandths

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Step-by-step explanation:

1500

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