Answer:
C
Step-by-step explanation:
you know the drill
Step 1. Multiply first equation with -3 and the second one with 2. You'll get:

Step 2. Add both equations together. You'll get:

, which gives x = -2
Step 3. Replace x = -2 in the first equation and calculate y.

The solution is: x=-2, y=5
U should know the area of rectangle is w*l
if we increase it by double or times 2 its area will be
A=2w*2wl
A=4wl
area would be 4 times of original one
Now u can get the answer
<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
Answer:
B. 51.7699^2
Step-by-step explanation:
Last 2 wrong because it is positive.
101.... is not the definite integral for the curve
51... purrfecto