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4 years ago

The space between the top of the valve stem and the rocker arm is called the

Mathematics

2 answers:

Misha Larkins [42]4 years ago

5 0

Answer:

The answer is valve clearance.

Step-by-step explanation:

The space between the top of the valve stem and the rocker arm is called the - valve clearance.

Valve clearances are the small gaps between the tops of the valve stems and the part of the mechanism which presses on them to open the valves.

These are important for the smooth and correct running of engines.

Studentka2010 [4]4 years ago

4 0

The space between the top of the valve stem and the rocker arm is called the valve clearance <span />

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A circle with area 100 pi has a sector with a central angle of 2/5 pi radians. What is the area of the sector?

Zarrin [17]

we know that

2pi radians (full circle) has an area of-----------------> 100pi

then

(2pi/5) radians----------------------------> X

X=(2pi/5)*100pi/2pi---------> 20pi units²

the answer is

20pi units²

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4 years ago

Thank for answer my question

Rasek [7]

Answer:

67.5?

Step-by-step explanation:

the top two looked like the same degree so solve 2x+10=145 ig

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3 years ago

what are the values of m∠abc, m∠cbf, and m∠dbe in the given figure? Explain or show your work. A good 55 points will go to the o

vesna_86 [32]

Step-by-step explanation:

m∠abc = m∠ebf = 58°

reason: vertical angles

m∠cbf = 180-m∠ebf = 180-58 = 122°

reason: Supplementary angles

m∠dbe = 90-m∠ebf = 90-58 = 32°

reason: complementary angles

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3 years ago

A linear function, f, has an x-intercept at (5,0) and a y-intercept at (0,3). Which best describes the shape of the graph of thi

deff fn [24]

From this statement, you can conclude that this is a negative linear function because the x-intercept is to the right of the y-intercept.

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3 years ago

Read 2 more answers

Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number

Dmitry [639]

Answer:

Part a) $2,50,18$

Part b) When Jenny divides the square root of her favorite positive integer by $\sqrt{2}$ , she gets an integer

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For $x=2$

$\sqrt{2}*\sqrt{2}=\sqrt{4}=2$ -----> the product is an integer

The number $x=2$ could be Jenny favorite positive integer

2) For $x=50$

$\sqrt{50}*\sqrt{2}=\sqrt{100}=10$ -----> the product is an integer

The number $x=50$ could be Jenny favorite positive integer

3) For $x=18$

$\sqrt{18}*\sqrt{2}=\sqrt{36}=6$ -----> the product is an integer

The number $x=18$ could be Jenny favorite positive integer

Part B)

1) For $x=2$

$\sqrt{2}/\sqrt{2}=\sqrt{1}=1$ -----> the result is an integer

2) For $x=50$

$\sqrt{50}/\sqrt{2}=\sqrt{25}=5$ -----> the result is an integer

3) For $x=18$

$\sqrt{18}/\sqrt{2}=\sqrt{9}=3$ -----> the result is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by $\sqrt{2}$ , she gets an integer

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3 years ago