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anygoal [31]
3 years ago
15

Can someone help meWhat is the missing numerator?

Mathematics
2 answers:
galina1969 [7]3 years ago
5 0

Answer:

d 2

Step-by-step explanation:

x/7 +13/14 = 17/14

double the first one so all the denominators are the same

2x/14+13/14=17/14

then subtract the second fraction from the thrid

2x/14=4/14

then we can divide by two so we are back to 7 as the demoninator

x/7=2/7

zavuch27 [327]3 years ago
5 0
X/7 + 13/14 = 1(3/14)

Convert the mix fraction into improper fraction:
(14 x 1) + 3 = 17 /14

X has to equal the difference between 13 and 17 which is 4

Remember since the lowest common denominator is 14 you would have to multiply x/7 by 2 on top and bottom and make sure that the x value is equal to 4

So ...

(2/7) + (13/14)

(4/14) + (13/14)

Add the number and keep the denominator the same

= 17/14 or 1(3/14)

Therefore the missing number is 2.

I hope this doesn’t sound too confusing :)

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Answer:

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When a figure rotates around a point, this point is called the
maxonik [38]

Answer:

Your answer is D. center of rotation!

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7 0
2 years ago
Read 2 more answers
Step by step please and thank you.
cupoosta [38]

Answer:

  the probability is 2/9

Step-by-step explanation:

Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).

  p(dime first) = 4/10 = 2/5

Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.

The joint probability of these two events occurring sequentially is the product of their probabilities:

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_____

<em>Alternate solution</em>

You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.

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8 0
3 years ago
In a jewelry store, rings makeup 5/9 of the inventory. Earrings make up 4/15 of the inventory. How many times greater is the rin
Free_Kalibri [48]
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To do this, we have to find a number that both 15 and 9 divide into. The smallest number that this can happen to is 45.

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So we have to multiply 15 by 3 in order to make it into 45. If we're changing the denominator, the numerator must change too, by the same multiplier.

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There rings inventory is 25/12 times bigger than the earrings inventory.
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