The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
The characteristic will spread and be more common throughout populations.
Step-by-step explanation:
Given
x² - 9x + 20 = 0
x² - ( 4 + 5) x + 20 = 0
x² - 4x - 5x + 20 = 0
x ( x - 4 ) - 5 (x - 4 ) = 0
(x - 4 ) ( x - 5 ) = 0
Either
x - 4 =0
x = 4
or
x - 5 =0
x = 5
x = 4 and 5
Hope it will help :)
Answer:
37
Step-by-step explanation:
10x40 = 400
2(39+42)+ 40 x 4 + 41 + X = 400
162 + 160 + 41 = 400 - X
400 - 363 = X
X= 37
Answer:
i think 4x+3y = -24 is answer
