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3 years ago

Find the sum of -7x^2-6x + 9 and 3x2 – 3 + 7. Please help

Mathematics

1 answer:

serg [7]3 years ago

6 0

Answer:

16 i think

Step-by-step explanation:

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Nth term of 4,1,-2,-5,-8

suter [353]

In the sequence, the numbers are going down by -3. So the nth term must start with -3n. To get from -3 to 4 you must add 7. This makes the nth term -3n+7.

4 0

3 years ago

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4y−7+2y=3(y−1)−1 answer for y

sammy [17]

The answer to your question is y=1

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3 years ago

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student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

Voting in 2004 presidential election George Bush received 53.25% of the total electoral votes and john Kerry received 46.75% of

vovikov84 [41]

Answer:

George Bush received 286 votes and John Kerry received 251 votes.

Step-by-step explanation:

Total number of votes = 537

% of votes received by George Bush = 53.25 %

No. of votes recieved by George Bush = $\frac{53.25}{100}$ ×537

= 285.95

≈ 286 votes.

The rest of the votes were for John Kerry,

=537 - 286

= 251

3 0

3 years ago

What two consecutive odd integers have a sum of 88?

Sindrei [870]

Answer:

What two consecutive odd integers have a sum of 88? x + x + 2 = 88 • 2x + 2 = 88 • 2x = 86 • x = 43, x + 2 = 45 • 43 + 45 = 88 • Ans: 43, 45 • They equal 88 and are both odd.

3 0

3 years ago