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Setler [38]
3 years ago
10

I need help with this​

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

Answer:

D

Step-by-step explanation:

The table gives us the squares of certain values, and can be used to find the square root of certain values as well. For example, if 6² = 36, we can say that √36 = 6. Given this information, we can say that √47.6 is 6.9, and √49 = 7. If we look at the square root graph (√x=y), we can see that as x goes up, y goes up, and when x goes down, y goes down.

Therefore, we can say that the square root of 48 is between 6.9 and 7. We don't know exactly where it is, as there is no formula given to find it, so what Gina can do is go through the values between 6.9 and 7.0 and look for √48

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Another way to check the sum of 104+34+228+877
vekshin1
We are asked to identify an another way to solve the given problem or this summation 104 + 34 + 228 + 887. We can verify it by doing of performing the summation in a reverse sequence such 877 comes first, then followed by 228, then followed by 34 and lastly added by 104. Therefore, the answer is 877 + 228 + 34 + 104.This is an another way to solve the given problem.
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3 years ago
3. Find the measure of the angle given.
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Answer:

80

Step-by-step explanation:

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zheka24 [161]

Answer:

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Past studies suggest this proportion will be about 0.15

This means that p = 0.15

Find the sample size needed if the margin of error of the confidence interval is to be about 0.04

This is n when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.15*0.85}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.15*0.85}

\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.04})^{2}

n = 17.5

Rounding up

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

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