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3 years ago

Determine if the 2 triangles are congruent.

Mathematics

1 answer:

Taya2010 [7]3 years ago

3 0

The answer is SAS which is C

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A soup recipe calls for 3 chopped onions. You want to make 1/5 of the recipe. How many onions will you need? Which proportion wi

Leya [2.2K]

Answer:

3/5, 1 onion,

Step-by-step explanation

1/5 x 3

8 0

3 years ago

Find the sum of the first five terms using the geometric series formula for the sequence 1/2, -1,2,-4…

sammy [17]

The sum of the first five terms is 11/2

<h3>How to determine the sum?</h3>

The series is given as:

1/2, -1,2,-4…

Calculate the common ratio of the series using

r = -4/2

Evaluate

r = -2

The sum is then calculated as:

$S_n = a\frac{1 - r^n}{1 - r}$

This gives

$S_n = \frac{1}{2} * \frac{(1 - (-2)^5}{1 + 2}$

Evaluate

$S_n = \frac{1}{2} * \frac{33)}{3}$

Evaluate

$S_n =\frac{11}{2}$

Hence, the sum of the first five terms is 11/2

Read more about series at:

brainly.com/question/11346378

#SPJ1

7 0

1 year ago

PLEASE I AM IN DESPERATE NEED OF HELP

erastova [34]

Answer:

C: H > 60

Step-by-step explanation:

H is 60 in or taller, underlined indicates that it's also 60 in, not just above it.

8 0

2 years ago

Find the zeros of polynomial x^2-3

Yakvenalex [24]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The required zeroes are ~

$\boxed{ \boxed {\sqrt{3}} \: \: and \: \: \boxed{- \sqrt{3} }}$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's equate the given polynomial with 0, to find its roots ~

that is ~

${x}^{2} - 3 = 0$

${x}^{2} - ( \sqrt{3} ) {}^{2} = 0$

$(x + \sqrt{3} )(x - \sqrt{3} ) = 0$

there are two cases,

Case # 1 - when (x + √3) = 0

$x + \sqrt{3} = 0$

$x = - \sqrt{3}$

and

Case # 2 - when (x - √3) = 0

$x - \sqrt{3} = 0$

$x = \sqrt{3}$

4 0

2 years ago

Read 2 more answers

In a recent year, grade 8 Washington State public school students taking a mathematics assessment test had a mean score of 281 w

sweet-ann [11.9K]

Answer:

The probability that the mean test score is greater than 290

P(X⁻ > 290 ) = 0.0217

Step-by-step explanation:

Step(i):-

Mean of the Population (μ) = 281

Standard deviation of the Population = 34.4

Let 'X' be a random variable in Normal distribution

Given X = 290

$Z = \frac{x -mean}{\frac{S.D}{\sqrt{n} } } = \frac{290-281}{4.44} = 2.027$

Step(ii):-

The probability that the mean test score is greater than 290

P(X⁻ > 290 ) = P( Z > 2.027)

= 0.5 - A ( 2.027)

= 0.5 - 0.4783

= 0.0217

The probability that the mean test score is greater than 290

P(X⁻ > 290 ) = 0.0217

6 0

3 years ago