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disa [49]
2 years ago
6

7k + 3f + 8k + 15f I need help with thia problem

Mathematics
2 answers:
morpeh [17]2 years ago
8 0
You basically have to add the like terms together.
7k+8k & 3f+15f
=15k. = 18f
Now your just left with 15k+18f because you can’t add them because they don’t have like terms
So they answer is 15k+18f
Hope this helped!
riadik2000 [5.3K]2 years ago
3 0

Answer:

15k + 18f

Step-by-step explanation:

combine the like terms

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This is a question on my partial fractions homework, but no matter what I try I can't figure it out..
Ierofanga [76]
\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}
\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}
\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)
\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3

So you have

\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}
=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}

where in the first integral we substitute x\mapsto x+1.

=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}
=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)
=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2
=\dfrac23+\ln\dfrac89
4 0
3 years ago
A ladder 15 feet long leans against the top of a structure at a 60 degree angle to the ground. What is the height of the buildin
Goshia [24]

Answer:

height of the building is 12.99 feet.

Step-by-step explanation:

given, try to analyse:

  • ladder 15 feet long.
  • 60 degree angle to the ground.

the height of the building is opposite to the angle 60° and given hypotenuse, the ladder of 15 feet long.

using sine rule:

sin(x) = \frac{opposite}{hypotenuse}

sin(60) = \frac{opposite}{15}

opposite = sin(60) *15

opposite = 12.99feet

Therefore the height of the building is 12.99 feet.

7 0
2 years ago
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zhuklara [117]

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The correct option is B.

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  • They also tend to have small campuses and class sizes; in fact, many classes have fewer than 20 students.
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Learn more about Liberal Arts College

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Oxana [17]
The last statement is true
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lord [1]

Answer:

range is 8 id k about domain

Step-by-step explanation:

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