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mylen [45]
3 years ago
8

please help me , this is the third one i have posted like this , if someone can go and help me on all of these is appreciate it

and i’ll give you free points pls , i’d appreciate it .. thank you

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer:

y^{1/4}

Step-by-step explanation:

When you have a power then a root like that, you have to divide the power by the root.

So, in this case, you have q square (y²) and a 8th root (8√).

So, you take your square (2) and divide it by the root (8), to get a new power of 2/8, or 1/4.

Let's verify it with y = 2

\sqrt[8]{2^{2} } = \sqrt[8]{4} = 1.19\\\\\\2^{1/4} = 1.19

So, both expressions equal the same thing, it means they're equivalent.

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Solve for d.<br> 2d+3=7d+18
algol [13]

Answer: d = -3

Step-by-step explanation:

2d+3=7d+18

-5d=15

d=-3

5 0
2 years ago
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Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
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\frac{dy}{dx} =  \frac{2x+3y \, sin(x)}{3cos(x)-2y}
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Answer:

Step-by-step explanation:

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