Volume equals to 1539.38 cm^3
yards/costumes:16/(5/2) = X/(19/2)
Cross multiply.
(5/2)x = 152
Multiply both sides by 2/5.
x = 101 1/3 yards
The answers are:
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[B]: "√12 " ; AND:
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[D]: "<span>√20" .
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Note: "Irrational numbers" have decimals that are: 1) non-terminating; AND: 2) non-repeating.
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Consider the answer choices given; and consider the given information that there "should be no more than one answer.
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Consider the following answer choices:
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Choice A) "</span><span>√9" = 3 . Rule out this choice.
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Choice C) "</span><span>√16" = 4 . Rule out this choice.
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Choice E) "</span><span>√25" = 5. Rule out this choice.
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We are left with 2 (two) remaining answer choices:
[B]: "</span>√12" ; and: [D]: "<span>√20" .
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If there are more than one answer, then these two choices should be the correct answer. However, let us explore these two choices, using a calculator.
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[B]: </span>"√12" = 3.4641016151377546
[D]: "√20" = 4.4721359549995794
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These two answer choices should the correct answers.
Volume
of a rectangular box = length x width x height<span>
From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>
<span>
where x is the height of the box or the side of the equal squares from each
corner and turning up the sides
V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x
To maximize the volume, we differentiate the expression of the volume and
equate it to zero.
V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>
<span>x^2 - 50/3x + 50 = 0
Solving for x,
x1 = 12.74 ; Volume = -315.56 (cannot be negative)
x2 = 3.92 ;
Volume = 1056.31So, the answer would be that the maximum volume would be 1056.31 cm^3.</span><span>
</span>
U fill the tank at 1:45 a.m......then u wait 1 1/2 hrs....
1:45 + 1 hr = 2:45.....2:45 + 30 minutes (because 1/2 hr = 30 minutes) =
3:15.....so u remove the liquid at 3:15 a.m.