Construct a 2x2 matrix whose element are given by i+j
1 answer:
9514 1404 393
Answer:
see below
Step-by-step explanation:
Assuming i and j refer to the row and column of a given element, that matrix would be ...
__
Rows are numbered top down, starting with 1. Columns are numbered left-to-right, starting with 1. The upper left element is in row 1, column 1, so has a value here of 1+1 = 2. Each number is one more than the one to its left. Each number is 1 more than the one above it.
You might be interested in
Answer: and
Step-by-step explanation:
Alright, lets get started.
The given equation is :
Adding 8 in both sides, it will become
To make it perfect square, we need to add 25 and subtract 25
Adding 17 in both sides
taking square root
So,
and
.. Answer
Hope it will help :)
Annually The amount after 10 years = $ 7247.295
quarterly compound after 10 years = $7393.5
Continuously interest =$7,419
Given:
P = the principal amount
r = rate of interest
t = time in years
n = number of times the amount is compounding.
Principal = $4500
time= 10 year
Rate = 5%
To find: The amount after 10 years.
The principal amount is, P = $4500
The rate of interest is, r = 5% =5/100 = 0.05.
The time in years is, t = 10.
Using the quarterly compound interest formula:
A = P (1 + r / 4)4 t
A= 4500(1+.05/4)40
A= 4500(4.05/4)40
A= 4500(1.643)
Answer: The amount after 10 years = $7393.5
Using the Annually compound interest formula:
A = P (1 + r / 100) t
A= 4500(1+5/100)10
A= 4500(105/100)10
Answer: The amount after 10 years = $ 7247.295
Using the Continuously compound interest formula:
e stands for Napier’s number, which is approximately 2.7183
A= $2,919
Answer: The amount after 10 years = $4500+$2,919=$7,419
More details :brainly.com/question/13307568
#SPJ9