Answer:
Hey there!
We have:



Let me know if this helps :)
Assume N students
Student 1 can get (n-1) papers
Student 2 can get (n-1) papers
Student 3 can get (n-1) papers
etc
Student N can get (n-1) papers
So for N students you can have N(n-1)
Answer:
The answer is C use a calculator
Step-by-step explanation:
not that hard lol
Answer:
6: 12
7: 14
8: 16
Step-by-step explanation:
You do the last (y) term given [18] minus the first (y) term [10] given divided by how many terms it takes to get from the last (y) term given minus the first (y) term given [4]. So the equation looks like this:
(18 - 10)/4= 8/4 = 2