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Sliva [168]
3 years ago
12

Dans 33 ans, Sarah aura le quadruple de son âge actuel.Quel âge a-t-elle aujourd'hui ?​

Mathematics
1 answer:
Oduvanchick [21]3 years ago
6 0

Answer:

Step-by-step explanation:

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Find the quotient.<br><br> 85,544 ÷ 289
finlep [7]
It is 296 that will the the right answer
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3 years ago
Find the volume of this square based pyramid. 5 cm 5 cm 5 cm. Round to the nearest tenth.
vodka [1.7K]

Answer:

41.666 cm³ or 41.7 cm³  rounded to the nearest tenth.

Step-by-step explanation:

Volume of a square pyramid = base length² × height ÷ 3

25 × 5/3 = 41. 666

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Find the commission.<br><br>Sales: $530 Commission Rate: 8% Commissions: ?
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42.40

Step-by-step explanation:

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3 0
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Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g


Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
5 0
4 years ago
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