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anygoal [31]
3 years ago
9

How do you solve systems by substitution for 3x + 3y =-4 5x=20

Mathematics
1 answer:
lina2011 [118]3 years ago
5 0
\left\{\begin{array}{ccc}3x+3y=-4\\5x=20&\ |divide\ both\ sides\ by\ 5\end{array}\right\\\\\left\{\begin{array}{ccc}3x+3y=-4\\x=4\end{array}\right\\\\substitute:\\\\3\cdot4+3y=-4\\12+3y=-4\\3y=-4-12\\3y=-16\ \ \  \ \ \ |divide\ both\ sides\ by\ 3\\y=-\frac{16}{3}\\\\Solution:x=4\ and\ y=-\frac{16}{3}\to(4;-\frac{16}{3})
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Answer:

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Questions?
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3 years ago
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Serjik [45]
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8 0
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Tasya [4]

Answer:

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In other words 2 x 4 = 8 = √2 x 4 but 4 can be simplified more (2 x 2) so 2 (previous 4) moves to the left of the square root leaving  2√2

To simplify a square root: make the number inside the square root as small as possible (but still a whole number)

or you can use a simplifying square root calculator.

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4 years ago
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