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3 years ago

Find the value of the variables in the simplest form

Mathematics

1 answer:

STatiana [176]3 years ago

6 0

Answer:

x = 3

Step-by-step explanation:

Using the tangent ratio in the right triangle and the exact value

tan60° = $\sqrt{3}$

tan60° = $\frac{opposite}{adjacent}$ = $\frac{x}{\sqrt{3} }$ = $\sqrt{3}$ ( multiply both sides by $\sqrt{3}$ )

x = 3

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PLEASE HELP!!!!! I NEED THIS FAST!!!!!!

ioda

Who says V1=V2?
if we simplify we get
(2/3)pir₁³=12pir₂²
for V1 to equal V2

a.
solve for r₁ to find r₁ as a function of r₂
(2/3)pir₁³=12pir₂²
times 3/2 both sides and divide by pi
r₁³=18r₂²
cube root both sides
r₁=∛(18r₂²)

if solve for r₂
(2/3)pir₁³=12pir₂²
divide by 12pi both sides
(1/18)r₁³=r₂²
squer root both sides
√((1/18)r₁³)=r₂

double radius of pond which is r1
√((1/18)r₁³)=r₂
r₁ turns to 2r₁ to double radius
√((1/18)(2r₁)³)=r₂double
√(8(1/18)(r₁)³)=r₂double
(√8)(√((1/18)(r₁)³))=r₂double
√((1/18)r₁³)=r₂ so
(√8)(r₂)=r₂double
(2√2)(r₂)=r₂double
the radius of the tank is multipled by 2√2

5 0

3 years ago

Y = -3x +10 3x +y = 5 substitution method

spayn [35]

Answer:

no solutions

Step-by-step explanation:

y = -3x +10

3x +y = 5

Substitute the first equation into the second equation

Let every instance of y in the second equation be replaced with -3x+10

3x+ (-3x+10) = 5

Combine like terms

10 =5

This is never true so there are no solutions

(These are parallel lines with the same slope but different y intercepts)

3 0

3 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

What is the slope of the line passing through the points (6,1) and (-3,-4)?

miskamm [114]

Answer:

5/9

Step-by-step explanation:

y2-y1/x2-x1 = 5/9

5 0

3 years ago

Select the correct answer.

rusak2 [61]

Answer:

the answer is E. none of the above

8 0

3 years ago