2 years ago

What type of angles are

Mathematics

1 answer:

jenyasd209 [6]2 years ago

6 0

Answer:

<z and <y are vertically opposite angle(V.O.A)

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Use substitution to solve the linear system of equations.

Ne4ueva [31]

Answer:

Step-by-step explanation: infinitely many solutions (please give brainliest)

6 0

2 years ago

In the diagram below, DE and EF are tangent to O. Which equation could be solved to find X, the measure of DF.

Brut [27]

Answer:

The answer to your question is letter D

Step-by-step explanation:

Formula

m∠E = $\frac{1}{2} ( DGF - DF)$

Data

m∠E = 48°

DGF = 228°

DF = x°

Substitution

48° = $\frac{1}{2} ( 228° - x°)$

Solution

2(48) = 228 - x°

96 = 228 - x°

96 - 228 = - x°

- 132 = - x°

x° = 132°

7 0

3 years ago

-105=7(1+2n) A:-8 B-4 C-10 D:-9 What’s the value of n in this equation?

Marat540 [252]

The answer is -8 or a

7 0

2 years ago

Help please only a and b

vesna_86 [32]

Answer:

A:48 B:45

Step-by-step explanation:

8 0

3 years ago

Consider the following functions.G(x) = 4x2; f(x) = 8x(a)

noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form $4x^2+C$ is an antiderivative of 8x

Step-by-step explanation:

A function F is an antiderivative of the function f if

$F'(x)=f(x)$

for all x in the domain of f.

(a) If $f(x) = 8x$ , then $G(x)=4x^2$ is an antiderivative of f because

$G'(x)=8x=f(x)$

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of f.

(b) Because

$\frac{d}{dx}(4x^2)=8x$

then $G(x)=4x^2$ is an antiderivative of $f(x) = 8x$ . Therefore, every antiderivative of 8x is of the form $4x^2+C$ for some constant C, and every function of the form $4x^2+C$ is an antiderivative of 8x.

8 0

3 years ago