W= 4/p+2 solve for p

Jonathan goes to the store and purchases 3 pencils for 0.28 each, and y number of erasers for 0.38 each. Write an expression tha

laiz [17]

Keywords

linear equation, variables

Step 1

Define the variables

Let

x-----> number of erasers

y-----> total cost

we know that

------> this is the linear equation that represent the situation

therefore

the answer is y = 0.84 + (0.38)x

5 0

3 years ago

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A trapezoid has angles 54 degrees, 54 degrees, x, and x. Look at the trapezoid shown. What is the measure of angle x? The measur

viktelen [127]

Answer: the answer is C 126°

3 0

2 years ago

Andy is buying a car.

serg [7]

7/100* 6500=455

6500-455=6045

6045/12=503.75

Andy pays 503.75 a month

8 0

3 years ago

A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili

Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

$18x = 3*31$

$x = \frac{31*3}{18}$

$x = 5.17$

So $\mu = 5.17$

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

$P(X \leq 3) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

So

$P(X \geq 4) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057$

$P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294$

$P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760$

$P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309$

So

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242$

Finally

$P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758$

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0

3 years ago

The volume of water in a tank is modeled by the function y = 1.15x3 – 0.1x2 + 2 where x is the number of minutes after the fauce

Thepotemich [5.8K]

Given:

The volume of water in a tank is modeled by the function

$y=1.15x^3-0.1x^2+2$

where, x is the number of minutes after the faucet filling the tank is turned on.

To find:

The y-intercept and what does it represent in this context?

Solution:

We have,

$y=1.15x^3-0.1x^2+2$

Substituting x=0, we get

$y=1.15(0)^3-0.1(0)^2+2$

$y=0-0+2$

$y=2$

Therefore, the y-intercept is 2 and it represents the volume of water in a tank before the faucet filling the tank is turned on.

7 0

3 years ago

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