Answer:
36 pages/4 hours
Step-by-step explanation:
The answer is 36 pages/4 hours
Answer:a
Step-by-step explanation:
I just did it
<h3>
1.Area of the parallelogram= 288 square units</h3><h3>
2.Area of the parallelogram=45 
</h3><h3>
3.Area of the trapezoid = 34 square in.</h3><h3>
4.Area of the trapezoid = 8 square ft</h3><h3>
5.Area of the rhombus= 27 square cm</h3><h3>
6.Area of the rhombus= 108 square in</h3><h3>
7.The area of the desktop is = 1200 square in</h3><h3>
8.The area of the rhombus is =84 
</h3><h3>
9.Area of the trapezoid = 240 square ft</h3>
Step-by-step explanation:
1.
Base =16 ft and Height = 18 ft
Area of the parallelogram = base × height
=16× 18 square units
= 288 square units
2.
Base = 9 m and height = 5 m
Area of the parallelogram = base × height
=(9×5) 
=45 
3 .
Height = 4 in and parallel sides are 12 in and 5 in
Area of the trapezoid =
square in.
= 34 square in.
4.
Height = 2 ft and parallel sides are 2 ft and 6 ft
Area of the trapezoid =
square ft
= 8 square ft
5.
Diagonals are 6 cm and 9 cm.
Area of the rhombus 
square cm
= 27 square cm
6. Diagonals are 12 in and 18 in
Area of the rhombus 
square in
= 108 square in
7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in
The area of the desktop is = (30 × 40 ) square in
= 1200 square in
8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.
The area of the rhombus =

=84 
9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft
Area of the trapezoid =
=
square ft
= 240 square ft
Step-by-step explanation:
Solve for k by simplifying both sides of the inequality, then isolating the variable.
Inequality Form:
K>2
Interval Notation:
(2,∞)
Answer:
11. Not enough information
12. You can say DB = DC by SAA congruence rule and CPCTC (Corresponding parts of congruent triangles are congruent)
Step-by-step explanation:
For 12, you can say ΔABD≅ΔACD because they have a side in common (AD) and they have 2 congruent angles. Thus, you can use the SAA congruence criterion. Then, you can use CPCTC (Corresponding parts of congruent triangles are congruent) to say that DB = DC.
Hope this helps :)