All categories

2 years ago

Can someone please help me, Im stuck on this question.

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

7 0

Answer:

D. 14

Step-by-step explanation:

4^2 - 2 (evaluate)

16 - 2 (calculate)

goblinko [34]2 years ago

6 0

Answer is D! Hoped it helped!

You might be interested in

Reason for 4 pleaseeee

Marina CMI [18]

The reason for statement 4 is CPCTC.

6 0

2 years ago

Which statement is true?

Nina [5.8K]

Answer: I think the answer is 1 in my opinion but not sure

4 0

2 years ago

Find the percent of change from 24°F to 39°F. Then state whether the percent of change is an increase or a decrease.

lara31 [8.8K]

Answer:

24F is a increase I belive and 39F is a decrease

4 0

2 years ago

What is the cash payment of a article costing RS.2020 allowing a discount of Rs.20 and levying 13% VAT?

belka [17]

The cash payment for the article is RS. 2,260.

A discount reduces the price of an item. The article becomes cheaper after the discount.

Cost of the article after the RS. 20 discount = RS. 2020 - 20 = RS 2000

VAT means value added tax. VAT increases the price of an item. The cost of the article increases by 13% after the VAT is levied,

Cost of the article = (100 + 13%) x 2000

1.13 x 2000 = RS 2,260.

To learn more about taxes, please check: brainly.com/question/25311567

7 0

1 year ago

Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

2 years ago

Can someone please help me, Im stuck on this question. ​

Can someone please help me, Im stuck on this question.