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WITCHER [35]
3 years ago
6

Can someone please help me, Im stuck on this question. ​

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
7 0

Answer:

D. 14

Step-by-step explanation:

4^2 - 2 (evaluate)

16 - 2 (calculate)

14

goblinko [34]3 years ago
6 0
Answer is D! Hoped it helped!
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What is 1/4 of 20? what is an equivalent fraction to 1/2?
Vinvika [58]
1/4 of 20 is 5.. and 5/10, 3/6, 2/4, 6/12 are all equal to 1/2
3 0
3 years ago
1. what are the domain and range of the function?
natta225 [31]

1) domain of the first is ( R ) because of its root(3) and its range is (R) because of its root again

2)and domain of the last , is [0,+infinity)

and for its range , you can draw it such as picture and will be [0,- infinity)

7 0
2 years ago
Read 2 more answers
How can 15/6 mixed number in simplest form
Assoli18 [71]
2 1/2 because you divide the 15 by 6 and 2 R.3   3 is half of 6 so you make it a half leaving you with 2.5 or fraction form:2 1/2
3 0
3 years ago
Given that P=x+y<br>Find P when:<br>x=11and y=6<br>what is p ?​
frutty [35]

Answer:

P = 17

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction

Step-by-step explanation:

<u>Step 1: Define</u>

P = x + y

x = 11

y = 6

<u>Step 2: Evaluate</u>

  1. Substitute:                    P = 11 + 6
  2. Add:                              P = 17

And we have our final answer!

4 0
3 years ago
Find a polynomial function with leading coefficient 1 that has the given zeros, multiplicities, and degree. Zero: 2, multiplicit
valkas [14]

Given:

Zero: 2, multiplicity: 3

Zero: 0, multiplicity: 2

Degree: 5

Leading coefficient = 1

To find:

The polynomial function.

Solution:

The general form of a polynomial is

P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}

where, a is a constant, c_1,c_2,...,c_n are zeroes with multiplicity m_1,m_2,...,m_n.

Using the given information and the general form of a polynomial, we get

P(x)=a(x-2)^{3}(x-0)^{2}

P(x)=ax^2(x^3-6x^2+12x-8)

P(x)=a(x^5-6x^4+12x^3-8x^2)

Leading coefficient is 1, so the value of a is also 1.

P(x)=1(x^5-6x^4+12x^3-8x^2)

P(x)=x^5-6x^4+12x^3-8x^2

Therefore, the required polynomial is P(x)=x^5-6x^4+12x^3-8x^2.

7 0
3 years ago
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