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disa [49]
3 years ago
12

Plsssssssssssssssss help me plsssssssssssssssssssssss

Mathematics
2 answers:
Alexandra [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Move two places to the right.

Alla [95]3 years ago
8 0

Answer:

The answer is B

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a veterinarian needs to know animals weight in kilograms. if 20 pounds is about 9 kilograms and a dog weights 30 pounds, use a r
ahrayia [7]

For this case we have the following conversion:

20 pounds = 9 kilograms

To use the table what we must do is find another relationship that allows us to find the weight in kilograms for 30 pounds.

For example, half the weight in pounds is half the weight in kilograms.

Therefore, the given conversion is:

10 pounds = 4.5 kilograms

So, for 30 pounds, we multiply this last ratio obtained by three on both sides:

30 pounds = 13.5 kilograms

Then, the table is:

Pounds 10 20 30

kilograms 4.5 9 13.5

Answer:

Using the ratio table the dogs weight is:

30 pounds = 13.5 kilograms

3 0
3 years ago
Read 2 more answers
Find the Area of the figure below, composed of a rectangle and a semicircle. The radius of the circle is shown. Round to the nea
liraira [26]

Answer: My friend told me it is 79

8 0
3 years ago
Simplify the following​
den301095 [7]

Answer:

1) 11\sqrt{3}

2) 2\sqrt{2}

3) 20\sqrt{3}  + 15\sqrt{2}

4) 53 + 12\sqrt{10}

5) -2

6) 7\sqrt{2}  - 5\sqrt{3}

Step-by-step explanation:

1) 2\sqrt{12} + 3\sqrt{48} - \sqrt{75}

=(2 × 2\sqrt{3} )+ (3 × 4\sqrt{3}) - 5\sqrt{3}

= 4\sqrt{3} + 12\sqrt{3} - 5\sqrt{3}

= 11\sqrt{3}

2) 4\sqrt{8} -2\sqrt{98} + \sqrt{128}

= (4 × 2\sqrt{2}) - (2 × 7\sqrt{2}) + 8\sqrt{2}

= 8\sqrt{2} - 14\sqrt{2} +8\sqrt{2}

= 2\sqrt{2}

3) 5\sqrt{12\\} - 3\sqrt{18} + 4 \sqrt{72}  +2\sqrt{75}

= 5× 2\sqrt{3} - 3×3\sqrt{2} + 4×6\sqrt{2} + 2×5\sqrt{3}

= 10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}

= 20\sqrt{3}  + 15\sqrt{2}

4) (2\sqrt{2}  + 3\sqrt{5} )^{2}

= 8 + 12\sqrt{10} + 45

= 53 + 12\sqrt{10}

5) (1+\sqrt{3} ) (1-\sqrt{3} )

= 1 - 3

= -2

6) (2\sqrt{6} -1) (\sqrt{3} -\sqrt{2}  )

= 2\sqrt{18}-2\sqrt{12}  -\sqrt{3}  +\sqrt{2}

= 2×3\sqrt{2} - 2×2\sqrt{3} - \sqrt{3} + \sqrt{2}

= 6\sqrt{2}  - 4\sqrt{3} -\sqrt{3} +\sqrt{2}

= 7\sqrt{2}  - 5\sqrt{3}

Hope the working out is clear and will help you. :)

5 0
3 years ago
Read 2 more answers
A maritime flag is shown. What is the area of the shaded part of the flag? Explain
Rom4ik [11]

Answer:

<em></em>Area = 72in^2<em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate  the Area:</em>

<em></em>Area_1 = Length * Width<em></em>

<em></em>Area_2 = 8in * (6in + 6in)<em></em>

<em></em>Area_2 = 8in * 12in<em></em>

<em></em>Area_1 = 96in^2<em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em>Area_2 = \frac{1}{2} * base * height<em></em>

<em></em>Area_2 = \frac{1}{2} * (6in + 6in) * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 12in * 4in<em></em>

<em></em>Area_2 = \frac{1}{2} * 48in^2<em></em>

<em></em>Area_2 = 24in^2<em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em>Area = Area_1 - Area_2<em></em>

<em></em>Area = 96in^2 - 24in^2<em></em>

<em></em>Area = 72in^2<em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0
3 years ago
Y=x^2 translate 4 units down and 3 units left
klasskru [66]

Answer: Hello! When a graph is translated 4 units down you are moving all of the y values. This makes it the easiest translation that we do, other than no translation! All you have to do is subtract 4. Your equation is y=x2 - 4. If you wanted to move the graph up it is addition and if you want to move it down it is subtraction. When you translate right to left it is more complicated! Hope this helps.  :))

3 0
2 years ago
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