Answer:
1.25
Step-by-step explanation:
In India
For

to be continuous at

, we need to have

Note that

means that

, but that

is *approaching* 5. We're told that for

, we have

We can write

and the limit would be

and so

is discontinuous.
start by diving 5 from each side so you are lrft with x on the left side, 40/5=8. now our equation is x=8 and that's the answer!