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liraira [26]
3 years ago
15

I’ve been trying on this question but in struggling. please help me

Mathematics
1 answer:
snow_lady [41]3 years ago
5 0

Answer:

x \geq 15

Step-by-step explanation:

Solving an inequality is very similar to solving an equation, one uses inverse operations. The only major difference between the two is that when one multiplies or divides an inequality by a negative number, one must remember to flip the inequality sign to ensure that the inequality remains true. In this situation, such a rule does not come into play.

\frac{x}{5} - 8 \geq -5

Inverse operations,

\frac{x}{5}-8 \geq -5\\              +8\\\\\frac{x}{5} \geq 3\\*5\\\\x \geq 15

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Rama09 [41]
Answer: x=15

Explanation: you can set 2x+100 = 5x+55 because they are corresponding interior angles.

Work:
2x+100 = 5x+55
2x+100-5x = 55
2x-5x = 55-100
-3x = -45
divide by -3 to cancel the negative and get x by itself
x = 15

Hope this helped! :)
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6. Fill in the smallest digit to make the number divisible by:
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Answer:

(i) 7164<u>0</u>, 32197<u>0</u>

(ii) 1<u>1</u>43, 47<u>2</u>05, <u>2</u>316

(iii) <u>1</u>428, 9<u>2</u>52, 721<u>2</u>

(iv) 2462<u>0</u>, 91<u>00</u>, 670<u>0</u>

(v) 1232<u>0</u>, 59<u>0</u>16, 4642<u>4</u>

Step-by-step explanation:

(i) In order for any number to be divisible by 5, its last digit must be <u>either 0 or 5</u>.

In this case, we should add a last digit, so we opt for <u>0</u> without any doubt since it gives a smaller number than <u>5</u> as the last digit: 71640 is smaller than 71645, the same way as 321970 is smaller than our second option, 321975.

(ii) If the sum of a number's digits gives a number divisible by 3, then the main number is also divisible by 3.

This means that we have to do some addition:

1_43: 1 + 4 + 3 = 8. Eight is not divisible by 3. But <u>9</u> is. So the smallest digit we can add for it to be divisible by three is <u>1</u>: <em>1143.</em>

47_05: 4 + 7 + 0 + 5 = 16. Since 16 is not, the next number that is divisible by 3 is 18, and therefore, the smallest digit we need here is <u>2</u>: <em>47205.</em>

_316: 3 + 1 + 6 = 10. Twelve is the next number divisible by 3, and that means <u>2</u> is the digit we choose: <em>2316.</em>

(iii) Only numbers that are divisible by both <u>2 and 3</u> are also divisible by 6.

_428: In order for a number to be divisible by 2, its last digit must be 0 or divisible by 2. That is already the case here.

4 + 2 + 8 = 14 which is not divisible by 3. But 15 is. So the smallest digit we need is <u>1</u>: <em>1428.</em>

9_52: The number will be divisible by 2. And 9 + 5 + 2 = 16 which is not divisible by 3 but 18 is. This means the smallest digit we need is <u>2</u>: <em>9252.</em>

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7 + 2 + 1 = 10 which is not divisible by 3 but 12 is. We will then choose to add <u>2</u>: <em>7212.</em>

(iv) A number is divisible by 4 only if the number that is formed by its two last digits is also divisible by 4..

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91__: Here we need to add both of the two last digits, and this should be the easiest example! All numbers that end in <u>00</u>, meaning they have a round number of hundreds, are divisible by 4! Therefore our option is: <em>9100.</em>

670_: In this case, we apply the same rule from the last example - and we choose <u>0</u>: <em>6700.</em>

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