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tresset_1 [31]
3 years ago
7

Can someone please help me?!

Mathematics
1 answer:
Nuetrik [128]3 years ago
3 0
V=x(8-2x)(10-2x) or expanded

V=x(4x^2-36x+80)

V=4x^3-36x^2+80x

...

If you were to graph the above equation for V(x) you will see a maximum point where the "y" value is maximized, but be careful as V will increase without bound at values of x that are not part of the domain, ie, in this case x<8/2, x<4 to have any meaning...The proper domain of this function is:

x=(0,4), Mathematically finding this point quickly is by differentiating it with respect to x...

dV/dx=12x^2-72x+80, The maximum volume will occur when dV/dx=0 and the x value is within the correct domain...

12x^2-72x+80=0  (using the quadratic formula for ease)

x=(72±√1344)/24, and since x<4

x≈1.472in  (to the nearest one thousandth of an inch)
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Answer:

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Step-by-step explanation:

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abruzzese [7]

Answer:

Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.

Step-by-step explanation:

i) let the number of 2 point question is x.

ii) let the number of 5 point questions be y

iii) total number of questions is 50

iv) therefore x + y = 50

v) it is also given that 2x + 5y = 145

vi) solving for the two equations found in iv) and v). Multiplying iv) by 2 we get

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vii) subtracting equation vi) from equation v) we get 3y = 45.

viii) Therefore y = 15.

ix) using the value in viii) and substituting in iv) we get x + 15 = 50.

    Therefore x = 50 - 15  = 35

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3 years ago
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Lena [83]

Answer:

Step-by-step explanation:

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marissa [1.9K]

Answer:

a) see below

b) 40x20 meters

Step-by-step explanation:

Write down what you know:

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A = x \cdot y

- The length of the fencing is 80 meters, so

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Now we have to combine these two equations above, and get rid of y in the process.

First rewrite the second as:

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So y = (80-40)/2 = 20 meters.

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2 years ago
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