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Snowcat [4.5K]
3 years ago
7

Which table shows a linear relationship

Mathematics
2 answers:
Furkat [3]3 years ago
8 0
The answer to the problem is B
drek231 [11]3 years ago
4 0

Answer:

B

Step-by-step explanation:

You might be interested in
Set up an linear equation and solve the following number word problem:
IRINA_888 [86]

Answer:

let the number be y

4(y-7)=48

y-7=48/4

y-7=12

y=12+7=19

I would appreciate if my answer is chosen as a brainliest answer

3 0
2 years ago
Our current equation is:
inessss [21]

Answer:

C

Step-by-step explanation:

subtracting 289 from both sides, will make one side will be equal to zero.

thus we can then easily solve for b.

can this answer get the brainliest tag?

8 0
3 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
what is the definition of value? i need that answer. if your Answered this question you gonna get 49 point!!!!!!!!!!!!!!!!!!!!!!
timurjin [86]

Answer:

In math, value can either refer to the result of a calculation or a variable or constant

5 0
3 years ago
Read 2 more answers
How do I solve 0.6(-13k-12)
Anton [14]

Answer:

-7.8k - 7.2

Step-by-step explanation:

Distribute 0.6 to the terms in the parentheses:

0.6(-13k - 12)

-7.8k - 7.2

So, the simplified expression is -7.8k - 7.2

4 0
3 years ago
Read 2 more answers
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