Answer:
She needs 168 more cels to draw to complete the film sequence
Step-by-step explanation:
120 Cells in 5 seconds
You want 12 seconds.
Ratio (Proportion)
120:5
Lets find the "unit rate" of the proportion.
120/5 = 24
So the unit ratio is 24:1
Now, we can deduce to it being:
120:5
240:10
264:11
288:12
She has 120 done.
So, 288-120 = 168.
She needs 168 more cels to draw to complete the film sequence
Answer:
A $3225
Step-by-step explanation:
Total = $3725
Dectuable = Able to be deducted
$3725 - $500 = $3225
The median of the data set is 4. The interquartile range is UQ-LQ 5-3=2. The mean of the first set is 3.5. The mean of the second set is 5.5. Since every score went up by two, the mean went up by two as well.
I hope that helps.
Yeah sure. It looks like one of those dilated problems since the smaller one is an exact copy of the bigger one except its, well you know, smaller. So it would be 5.
Answer:
The Domain of the function is the set of ALL Real numbers
Step-by-step explanation:
To find the Domain of a function, one has to examine if there are any mathematical restrictions in the function's expression that could reduce the set of Real numbers to be used in estimating all the possible function's outputs.
Typical examples are:
1) There are x-variables in the denominator of the function (you must consider then which values of x could render a zero in the denominator and therefore make it undefined)
2) the variable x appears inside an even root (like a square root), then you have to consider which values of x are not allowed if they render a negative value inside the root
3) if x appears inside logarithmic expressions (you need to exclude from the domain those x-values that render negative the expression inside the logarithm)
Another important rule to remember,is that all polynomial functions (like the one given in this case) always have for Domain the full number line (all Real numbers) because any Real number used will render another Real number via multiplications, subtractions and additions (which are the operations involved in a polynomial expression)
