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2 years ago

What is the product of 2X plus 3 and 4X squared minus 5X plus 6

1 answer:

5 0

The product of something means multiplying the terms together.

(2x+3) (4x^2-5x+6)

Secondly you need to distribute the terms to each other (Think of problems like FOIL)

2x * 4x^2 + 2x(-5x) + 2x * 6 + 3 * 4x^2 + 3(-5x) + 3 * 6

Then you must take into account that some of the numbers are negative. (minus-plus rules!)

2x * 4x^2 - 2x * 5x + 2x * 6 + 3 * 4x^2 - 3 * 5x + 3 * 6

Now is the tricky part of simplifying everything.

2x * 4x^2 = 8x^3

2x * 5x = 10x^2

2x * 6 = 12x

3 * 4x^2 = 12x^2

3 * 5x = 15x

3 * 6 = 18

8x^3 - 10x^2 + 12x + 12x^2 - 15x + 18

Then you group like terms.

8x^3 - 10x^2 + 12x^2 - 3x + 18

8x^2 + 2x^2 - 3x + 18

The trickiest part of this is distributing all of the terms within the parentheses, once you've done that, it's smooth sailing!

You might be interested in

Can you make 24 from the numbers 3, 6, 8 and 2, using all the numbers? You can only use the operations: + - x / ( )

Andre45 [30]

Answer:

you can do 3 x 6 + 8 - 2

Step-by-step explanation:

3 × 6= 18

+8= 26

-2= 24

hope this Helps :)

4 0

2 years ago

A scalene triangle has two sides that are equal in length.

iogann1982 [59]

false that not true they have all unequal sides

8 0

2 years ago

What is the measure of angle c?

s344n2d4d5 [400]

Answer:

50 degrees

Step-by-step explanation:

Okay! So first off, because this is NOT a right triangle, we can't use soh cah toa. That means we can either use the law of sines or the law of cosines.

Because we only have sides here and no angles, we are forced to use the law of cosines.

c^2 = a^2 + b^2 − 2ab cos(C)

c = 6

b = 7.5

a = 6.5

36 = 6.5^2 + 7.5^2 - 2(6.5)(7.5)cos(C)

36 = 98.5 - 97.5cos(C)

-62.5 = -97.5cos(C)

0.641 = cos(C)

angle C = cos^-1(0.641)

angle C = 50.13 which is around 50 degrees

Remember! A dumb thing i always used to do in geometry was use radians instead of degrees, be sure to use degrees here because you are looking for degrees. Radians are for things involving not degrees, but PI.

5 0

2 years ago

Alana rode her bicycle 10 miles on Tuesday and 20 miles on Wednesday. What is the mean absolute deviation of this data?

stiks02 [169]

Answer:

Step-by-step explanation:

Given that :

Miles ridden in Tuesday = 10

Miles ridden on Wednesday = 20

Sample size, n = 2

Mean :

(10 + 20) / 2

= 30 /2

= 15

Mean absolute deviation :

(|10 - 15| + |20 - 15|) / 2

(5 + 5) / 2

10 / 2

= 5

3 0

1 year ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

2 years ago