Question

9. Write a polynomial function in factored form with zeros at -2, 5, and 6.

Answer 1

Answer:

f(x) = ( x+2)(x-5)(x-6)

Step-by-step explanation:

We can write the equation with zeros at b1,b2,b3

f(x) =a( x-b1)(x-b2)(x-b3)  where a is a constant and b1 b2 b3 are the zeros

f(x) = a( x- -2)(x-5)(x-6)

f(x) = a( x+2)(x-5)(x-6)

We can choose a since we are not given any more information about the function.  Let a = 1

f(x) = 1( x+2)(x-5)(x-6)

f(x) = ( x+2)(x-5)(x-6)